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Keep an index at the end of a condition #29

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Merged
mikebarkmin merged 1 commit into from
Oct 29, 2026
Merged

Keep an index at the end of a condition #29

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2 changes: 1 addition & 1 deletion packages/struktolab/src/common/pseudocode-parser.js
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Original file line number Diff line number Diff line change
Expand Up @@ -114,7 +114,7 @@ function placeholder() {
* "x > 0" → { text: "x > 0", columnWidths: null }
*/
function extractColumnWidths(str) {
const match = str.match(/^(.*?)\s*\[([0-9.,\s]+)\]\s*$/);
const match = str.match(/^(.*?)\s+\[([0-9.,\s]+)\]\s*$/);
if (match) {
const text = match[1].trim();
const widths = match[2].split(",").map(s => parseFloat(s.trim())).filter(n => !isNaN(n));
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11 changes: 11 additions & 0 deletions packages/struktolab/src/common/pseudocode-parser.test.js
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Expand Up @@ -15,3 +15,14 @@ test("keeps the body of a line it does not understand", () => {
const out = roundTrip('while x > 0:\n x = x - 1\n output("x")\ny = 1');
assert.equal(out, 'while x > 0:\nx = x - 1\noutput("x")\ny = 1');
});

test("keeps an index at the end of a condition", () => {
const code = "switch notes[0]:\n case 1:\n y = 1";
assert.equal(roundTrip(code), code);
});

test("reads column widths after the condition", () => {
const tree = parsePseudocode("if a[0] > 1 [0.7, 0.3]:\n y = 1\nelse:\n y = 2", KEYWORDS_EN);
assert.equal(tree.followElement.text, "a[0] > 1");
assert.deepEqual(tree.followElement.columnWidths, [0.7, 0.3]);
});
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